内网2073 城主GeassCode
Description
GeassCode凭借自己在topcoder上的超凡表现,赢得了国王的喜爱,国王赏赐他一座城池。这座城池里有n个 村子,m条路连接这些村子。坐上城主的GeassCode决定要修路,他打算用最少的代价把所以的村子连在一起。据探子回报,有些村子之间虽然原来没有路 径,但是可以强行的去建一条路。GeassCode想知道,如果强行在某两个村子之间建一条路,最后的总花费是多少?
GeassCode凭借自己在topcoder上的超凡表现,赢得了国王的喜爱,国王赏赐他一座城池。这座城池里有n个 村子,m条路连接这些村子。坐上城主的GeassCode决定要修路,他打算用最少的代价把所以的村子连在一起。据探子回报,有些村子之间虽然原来没有路 径,但是可以强行的去建一条路。GeassCode想知道,如果强行在某两个村子之间建一条路,最后的总花费是多少?
心情就像倒数第二楼那样。
CLJ,我也保证不打死你……
PS:最后一楼朱大神还暴露了。
Time Limit: 1000MS Memory Limit: 10000K
Total Submissions: 17734 Accepted: 9405
A rooted tree is a well-known data structure in computer science and engineering. An example is shown below:
In the figure, each node is labeled with an integer from {1, 2,...,16}. Node 8 is the root of the tree. Node x is an ancestor of node y if node x is in the path between the root and node y. For example, node 4 is an ancestor of node 16. Node 10 is also an ancestor of node 16. As a matter of fact, nodes 8, 4, 10, and 16 are the ancestors of node 16. Remember that a node is an ancestor of itself. Nodes 8, 4, 6, and 7 are the ancestors of node 7. A node x is called a common ancestor of two different nodes y and z if node x is an ancestor of node y and an ancestor of node z. Thus, nodes 8 and 4 are the common ancestors of nodes 16 and 7. A node x is called the nearest common ancestor of nodes y and z if x is a common ancestor of y and z and nearest to y and z among their common ancestors. Hence, the nearest common ancestor of nodes 16 and 7 is node 4. Node 4 is nearer to nodes 16 and 7 than node 8 is.
Farmer John's cows refused to run in his marathon since he chose a path much too long for their leisurely lifestyle. He therefore wants to find a path of a more reasonable length. The input to this problem consists of the same input as in "Navigation Nightmare",followed by a line containing a single integer K, followed by K "distance queries". Each distance query is a line of input containing two integers, giving the numbers of two farms between which FJ is interested in computing distance (measured in the length of the roads along the path between the two farms). Please answer FJ's distance queries as quickly as possible!
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65768/65768 K (Java/Others) Total Submission(s): 1992 Accepted Submission(s): 440
Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 65535/65535 K (Java/Others) Total Submission(s): 3532 Accepted Submission(s): 813